I need help with algebra 2! Solve the equation. Check for extraneous solutions. 2|7-7x|=2x+4
Solve each equation. Check for extraneous solutions. Equation: |5x-1|+7=3x Here's what I did: |5x-1|+7=3x -7 -7 |5x+1|=3x-7 5x-1=3x-7 OR 5x-1=-(3x-7) +1 +1 5x=3x-6 -3x -3x 2x=-6 2 2 x=-3 OR 5x-1=-(3x-7) 5x-1=-3x+7 8x = 8 x = 1 So, x=-3 or x=1. CHECK: |5x-1|+7=3x
|5(-3)-1|+7=+3(-3) |-15-1|+7=-9 |-16|+7=-9 16+7=-9 23=9 But 23 doesn't equal 9. At first I thought it was just an exraneous solution. But then I checked the second number: |5x-1|+7=3x |5(1)-1|+7=3(1) |5-1|+7=3 |4|+7=3 4+7=3 11=3 But again, 11 doesn't equal 3. Your work is correct. Both "solution" are extraneous. --- If you graph the left side and the right side of the equation separately, you will see that they do not intersect, i.e. they are never equal.
Its not graphing
The answers are a. x=3/2 x=5/6 b. x=3/2 x=5/8 c. x=5/8 d. x=3/2
A. x=3/2 x=5/6 is the correct 1
Thank you!
no prob gimme a medal
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