Question

how do you find the focus and directrix of the parabola x^2=-1/4y click attached http://bamboodock.wacom.com/doodler/4ba1c05a-4a28-4ca7-9f63-39fc75232f31

Answer 1

HELPP

Answer 2

standard equation is
(x-a)^2=4C(y-b)
where a,b are vertex and C is the distance between the focci.

Answer 3

so in this case write in the standard form

(x-0)^2=-1/4(y-0)

can you tell me vertex now ??

Answer 4

so it would be 0, -1/16?

Answer 5

nopes!!
it should be (0,0) look a and b are zero in this case.

Answer 6

oh i got it thank youuuu!!

Answer 7

you 're welcome :)