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Which of the following represents x^2-16/x^2-4x in simplified form?
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did u mean this ?: \[\large{\frac{x^2-16}{x^2-4x}}\]
@jrosesweet
Yes :) @mathslover
\[\large{\frac{(x+4)(x-4)}{x(x-4)}}\] right?
since : \[\large{a^2-b^2=(a+b)(a-b)}\]
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now cancel out x-4 \[\large{\frac{(x+4)\cancel{(x-4)}^1}{x\cancel{(x-4)}^1}}\] \[\large{\frac{x+4}{x}}\]
\[\large{\frac{x}{x}+\frac{4}{x}}\] \[\large{1+\frac{4}{x}}\]
choices given ?@jrosesweet
You got it right that was one of the choices!
:D i am mathslover dude ..
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