One solution of the equation 6x^2-19x+3=0 is 1/6
What is the other solution?

Question

One solution of the equation 6x^2-19x+3=0 is 1/6
What is the other solution?

anonymous · Answer

You can try doing the quadratic formula.

lgbasallote · Answer

if 1/6 is a solution that means

x = 1/6 is a root

that means 6x - 1 is a factor

so just divide 6x^2 - 19x + 3 by 6x - 1

anonymous · Answer

How do I do that?

lgbasallote · Answer

long division? synthetic division? isnt that your lesosn?

anonymous · Answer

sum of the roots of Quadratic equation 
ax^2+bx+c=0 is
-b/a
so in our case
a=6
b=-19
so the sum of roots should be ,let unknown root is r
1/6+r=-(-19)/6
$$\Large r+\frac{1}{6}=\frac{19}{6}$$
OR
$$\Large r=\frac{19}{6}-\frac{1}{6}$$
simplify it and you got your answer !!

lgbasallote · Answer

lol

anonymous · Answer

yeah !!!!

lgbasallote · Answer

wonder why wolfram disagrees though

anonymous · Answer

let me check my Algebra then .

lgbasallote · Answer

lol jk

anonymous · Answer

It is $$Sum = -\frac ba = \frac{19}{6}$$

anonymous · Answer

So, you suntract 1/6 to get 18/6 which simplifies...

anonymous · Answer

lol i was right !!!!!!!

anonymous · Answer

Yup XD Just always remember the sign rule for these types of things ;)

anonymous · Answer

@lgbasallote wolfram agrees with me :P

lgbasallote · Answer

didnt you see the lol jk? lol

anonymous · Answer

oops!!! now i saw lol jk :P

anonymous · Answer

Sorry guys my computer froze!!

anonymous · Answer

So the other solution is 18/6 ?!?

anonymous · Answer

yes 18/6=3

anonymous · Answer

Well spankyou. Spankyou all very much.