blah blah
I'd like to respond to that with this: http://openstudy.com/code-of-conduct Good luck!
\[\text {blah blah}=2\text{blah}\]
Or \(\text{blah}^2\)
\[(blah)^2\]
Okay guys. I am closing this thread - thanks!
a space odes not indicate multiplication
A space does not indicate addition either. ;P
\[1 ~\frac 12=1+\frac 12\]
Oh, well.
\[\large{:P}\]
But that doesn't have a space.\[{1 } {1 \over 2} \ne {1} \; {1 \over 2} \]
which is bigger parth?
\[1{1 \over2 } \ne 1 \quad{1 \over 2} \]
are they not equal?
\[a=b\\a^2=ab\\a^2-b^2=ab-b^2\\(a+b)(a-b)=b(a-b)\\a+b=b\\a=b\therefore a+b=b+b=2b=b\\2=1\]
^ Yep. The latter does not make sense. @UnkleRhaukus
@badreferences Division by zero? Let me call the police!
Shh... don't tell the high school students. Tell them this early, so they think they broke math.
ahaha got lots of attention for that one chill guys just trying to stay awake its 4 am lol l hope l didnt offend anybody
U guys are funny as hell l am lol l even woke my chimpanzee up lol
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