Mathematics
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OpenStudy (anonymous):
–2(x – 3) ≥ 5 – (x + 3) HELP INEQUAILTY
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OpenStudy (anonymous):
get rid of the parentheses first using the distributive property
OpenStudy (anonymous):
@satellite73 okay so then we would have -2x + 6 ≥ 5 – 3x?
OpenStudy (anonymous):
careful here
OpenStudy (anonymous):
left side is correct, you would get \(-2x+6\) but the right side should be \(5-x-3=2-x\)
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OpenStudy (anonymous):
that is, \(5 – (x + 3)=5-x-3=2-x\) by the distributive law
OpenStudy (saifoo.khan):
similar*
OpenStudy (anonymous):
so start with
\[ -2x + 6 ≥ 2-x\] then add \(2x\) to both sides, and subtract \(2\) from both sides that you will be done
OpenStudy (anonymous):
6 + 4 ≥ 4 - x and then what im confused for this part ?? @satellite73
OpenStudy (anonymous):
–2(x – 3) ≥ 5 – (x + 3)
-2x+6>= 5-x-3
6-2x>=2-x
6-2>=-x+2x
x<=4
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OpenStudy (anonymous):
(look here careflly)
6-2x>=2-x
6-2>=-x+2x
x<=4
OpenStudy (anonymous):
how did you do it explain in words??
OpenStudy (anonymous):
-2x+6>= 5-x-3
Did u understand up to here
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
now add -2x to both sides:
-2x+6>= 5-x-3
-2x+6+2x>=2-x+2x
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OpenStudy (anonymous):
got it?
OpenStudy (anonymous):
kk
OpenStudy (anonymous):
@sauravshakya
OpenStudy (anonymous):
so what do u get?
OpenStudy (anonymous):
-2x+6+2x>=2-x+2x
after this
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OpenStudy (anonymous):
6-2x>=2-x
OpenStudy (anonymous):
add +2x on both sides
OpenStudy (anonymous):
6-2>=-x+2x
OpenStudy (anonymous):
????
OpenStudy (anonymous):
@sauravshakya
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OpenStudy (anonymous):
now, 4>=x
OpenStudy (anonymous):
got it?
OpenStudy (anonymous):
yea
OpenStudy (anonymous):
and thats the answer
OpenStudy (anonymous):
@SchoolFreak got it?
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OpenStudy (anonymous):
noo
OpenStudy (anonymous):
how did you get 4 >= x
OpenStudy (anonymous):
6-2>=-x+2x (from there)
OpenStudy (anonymous):
6-2=4 (right?0