Question

Given: sin A = –
3/5 , cos B =15/17 , angle A in Quadrant III and angle B in Quadrant I.
Find the values of the following sin 1/2 a

Answer 1

can you please help me?

Answer 2

sure

Answer 3

Do u know that SinA = 2 sinA/2 * cosA/2

Answer 4

i am given this formula

Answer 5

now squaring both sides give:
(sinA)^2 =4 (sinA/2)^2(COSA/2)^2

Answer 6

oh....that can also be used

Answer 7

so what should i do?

Answer 8

do u want to go with my method.....

Answer 9

yes

Answer 10

so are u clear up to here
(sinA)^2 =4 (sinA/2)^2(COSA/2)^2

Answer 11

yes