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OpenStudy (anonymous):
solve for t? 1863.3=(1.00675)^4t
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OpenStudy (precal):
log both sides
OpenStudy (anonymous):
im still confuse.
OpenStudy (anonymous):
equation please?
OpenStudy (ghazi):
log(1863.3) = log(1.00675^4t)....now log (A^B)= B*log (A)....now you can do it
OpenStudy (precal):
drop the power in front of the log
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OpenStudy (ghazi):
yes...it is the property of log
OpenStudy (anonymous):
thankss
OpenStudy (precal):
hope that helps, if not let me know
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