Question

Please Help!! Multiply (-2n)^2 times (3n^6)^2=?

Answer 1

\((-2n)^2=4n^2\) and \(( 3n^6)^3=9n^{12}\) for a start

Answer 2

ok typo on the last one
should be
\[(3n^6)^2=9n^{12}\]

Answer 3

in any case your job is to multiply
\[4n^2\times 9n^{12}\] multiply \(4\times 9\) and add the exponents to get your answer

Answer 4

ok