Can someone please help me now with writing the equation of the line in slope-intercept form with a slope of -6 and a y-intercept of 9 ?
FLVS? or homework
flvs , they did not explain right to me i dont really get it and i read it like 9 times
ok what module is it?
y-intercept=c=9 and m(slope)=-6..... So slope-intercept form is y=mx+c.......U can put the values
module 4.03
k give me a second
y=mx+b so y=-6x+9
thank you so much :)
ur welcome
what is a FLVS ?
florida virtual school
one more question sorry can you help me with how to do the equation of the line passing through the point (2, -4) and parallel to y = 3x - 6.
we have to calcuate the equation in slope-intercept form ....rite? now U are given a point..... and an equation.... If the required line is paralle to y = 3x - 6.... then the new equation should have the same slope... which is m=3.... so use point-slope form ..... to find an equation and then convert it into slope-intercept form if required..... :)
so the answer is going to be y = 3x-2 ??
a little mistake... it will be y=3x-10
mann -___- thanks anyways :) do you give tutorails ? like on a webiste or something bc yours good at this and i really need the help
no, I didn't...... But I can give I think so.... on the subjects i knew a bit.... But where to give I don't know..... Well, in analytical geometry... I found myself good....... But not that much good... May be
ok thanks anyways :)
My pleasure. If u need help anytime can post... Will try to help.......
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