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Mathematics 6 Online
OpenStudy (anonymous):

how many solutions has it? x^2+y^2+z^2=2xyz

OpenStudy (anonymous):

^ i think the answer is wrong.

OpenStudy (anonymous):

yes i agreed with RyanL.

OpenStudy (anonymous):

The solution is \[ x=y=z=0 \] It is a trivial solution to this problem.

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