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Mathematics 15 Online
OpenStudy (anonymous):

please help (x^2-25)(x+2i)(x-2i) find the zeros

OpenStudy (anonymous):

(x^2-25)(x+2i)(x-2i) (x+5)(x-5)(x+2i)(x-2i)

OpenStudy (anonymous):

now equate it to zero and find zeros

OpenStudy (anonymous):

can u?

OpenStudy (anonymous):

so -5,5

OpenStudy (anonymous):

idk about the imaginary ones

OpenStudy (anonymous):

yep

OpenStudy (anonymous):

how would it be though?

OpenStudy (anonymous):

nope they cannot be zeros

OpenStudy (anonymous):

because zeros has to be a real number

OpenStudy (anonymous):

so theres no answer?

OpenStudy (anonymous):

for those ones?

OpenStudy (anonymous):

-5, and 5 is the answer

OpenStudy (anonymous):

thank you so much :)

OpenStudy (anonymous):

WELCOME

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