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Determine the direction and vertex of the parabola formed by the given equation. x = 16(y + 2)^(2) + 3 The parabola opens to the ______, and the vertex is _______.
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you want to make it look like \[a(x-h)=(y-k)^2\] to find the vertex of \((h,k)\)
since the \(y\) is squared and the coefficients of \(x\) and \(y^2\) are positive, it opens to the right
what is the answer to the vertex is it (3, 2)
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