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Physics 10 Online
OpenStudy (anonymous):

When a 20.0-ohm resistor is connected across the terminals of a 12.0-V battery, the voltage across the terminals of the battery falls by 0.300 V. What is the internal resistance of this battery?

OpenStudy (anonymous):

think of the battery as a resistor and a power source |dw:1344752413514:dw|

OpenStudy (kainui):

First off, draw out the circuit and label everything to be something like this: |dw:1344752177703:dw| So I've designated R=20.0 ohm E=12.0 volts r=internal resistance and the voltage drop was .3 volts.

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