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What is the equation in standard form of the line which passes through (1, –3) and has a slope of 2?
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2x – y = 5 2x – y = –5 2x + y = 5 2x + y = –5
y+3=2(x-1)..now you can do it
first you need the point slope formula \[y-y_1=m(x-x_1)\] with \[m=2,x_1=1,y_1=-3\]
y-(-3)=2(x-1)
y+3=2x-2
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2x+y=5..?
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