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What are the asymptotes of the hyperbola given by the equation x^2/144-y^2/1=1
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slope is the sqrt of y/x denoms
since the center point is the anchor to the slopes; y = +-mx should suffice
The asymtopes are y = 1/12x and y = -1/12x. (sorry mods!)
..... and what would compel you to this life of crime and debauchery? why?!?!?
huh? here are the chpices.y = 6x y =1/36 x y =1/ 6x y = 36x
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none of the them
wiat .... maybe
nah, none of them
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