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3x + 2x2 - 9
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2x^2+3x-9=0.....\[x= (-3\pm \sqrt{(-3)^2}-4*2*-9)/2*2\]
x=\[-3\pm9/6\]
now you can find x
how
by solving above addition and division you'll get x= -2 and 1
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im confused
x= (-3+9)/6=6/6=1 and x= (-3-9)/6=-12/6=-2
solve that?
that's it...you have x=-2 and 1
im soooo lost idk what to do
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just factorize your equation it will be (2x-3)(x+3)
idk
its out 54 or 180
what's that ....54 and 180?
whats what
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@Ganpat you know?
@ghazi is right.. if u cannot factorize simply, than use the following formula.. |dw:1344892860005:dw|
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