Homework Help Please!!!

Question

anonymous · Answer

attachment

jim766 · Answer

both of the denominators are difference of two squares, do you know how to factor them?   x^2-1 = (       )*(        )

anonymous · Answer

Please Help!!! :(((

anonymous · Answer

Thank You!

anonymous · Answer

$$a^2 - b^2 = (a-b)(a+b)$$

anonymous · Answer

I know how to factor i need help with the actual prob.

anonymous · Answer

In actual problem:

a = x and b = 1 for first part..

Use the formula that I have written above..

anonymous · Answer

(x-1) (x+1)

anonymous · Answer

Yes great..

Now for second part:

a = x and b = y..

Go for same..

anonymous · Answer

(x-y) (x+y)

anonymous · Answer

Great..

anonymous · Answer

Now you know denominator must not be 0..

anonymous · Answer

$$(x-1)(x+1) \ne 0 \;\; and \;\; (x+y)(x-y) \ne 0$$

Try to find x from here.

anonymous · Answer

pardon?

anonymous · Answer

Can you simply tell what will be the values of x for which:

$$(x-1)(x+1) = 0$$

anonymous · Answer

This thing when it will become 0???

Try to put x = 1 2 -1 etc values to x and tell me for what values of x you are getting 0..

Or you can do one more thing:

Separately put them to 0:

$$x - 1 = 0$$

$$x+1 = 0$$

Now find x..

anonymous · Answer

1 for the first one and -1 for the second

anonymous · Answer

Yes..

Similarly do for (x-y)(x+y)

anonymous · Answer

y-y=0 -y+y =0 ...?

anonymous · Answer

So you got four values:

x = 1, -1, y, -y..

So now your work is to fill that blanks with these..

anonymous · Answer

Thanks for the help! It is greatly appreciated!