Question

Write an equation of the line containing the given point and perpendicular to the given line.

(0,6); 9x+8y=5

Answer 1

first isolate y...
9x+8y=5
8y=-9x+5
y=(-9/8)*x+5/8
the perpendicular slope of -9/8 is 8/9 so sub that in with the given point into point slope equation
y-y1=m(x-x1)
so...
y-6=8/9(x-0)
so y=(8/9)*x+6 would be your answer