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Mathematics 21 Online
OpenStudy (anonymous):

what is the value of (x^n-y^n)/(x-y) as x------>y

OpenStudy (anonymous):

@sami-21 , @mukushla

OpenStudy (anonymous):

I got----------> n y^(n-1)

OpenStudy (anonymous):

better to use this identity\[x^n-y^n=(x-y)(x^{n-1}+x^{n-2}y+...+xy^{n-2}+y^{n-1})\]

OpenStudy (anonymous):

yep thats right

OpenStudy (anonymous):

Is it right?

OpenStudy (anonymous):

THANX

OpenStudy (anonymous):

welcome

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