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what is the value of (x^n-y^n)/(x-y) as x------>y
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@sami-21 , @mukushla
I got----------> n y^(n-1)
better to use this identity\[x^n-y^n=(x-y)(x^{n-1}+x^{n-2}y+...+xy^{n-2}+y^{n-1})\]
yep thats right
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THANX
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