Question

if
(b^4) + (1/b)^4 =6

then find the value of
(b+ i/b)^16
where i = sqrt(-1)

Answer 1

@mukushla ??

Answer 2

use this
\[(b^2-\frac{1}{b^2})^2+2=b^4+\frac{1}{b^4}=6\]\[(b^2-\frac{1}{b^2})^2=4\]\[b^2-\frac{1}{b^2}=(b+\frac{i}{b})^2-2i=\pm2\]

Answer 3

omg!! buddy,,which planet are you from? seriously??

Answer 4

thanks a lot!

Answer 5

lol....yw :)