Question

6. Use factoring to solve the quadratic equations below, if possible. a. 2x2 + 3x - 54 = 0

Answer 1

\[\large{2x^2+3x-54=2x^2+12x-9x-54}\]
right?

Answer 2

\[\large{2x^2+12x-9x-54=0}\]
\[\large{2x(x+6)-9(x+6)=0}\]
\[\large{(2x-9)(x+6)=0}\]
\[\large{\textbf{Hence, either 2x-9=0 or x+6=0}}\]
\[\large{2x-9=0 \space 2x=9 ,\space x=\frac{9}{2}}\]
\[\large{x+6=0 ; x=-6}\]

Answer 3

thanks