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For the function f(x)=1/3x−4, find the value of x for which f(x)=x
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plz help asap!!!
y = (1/3)x-4 so x = 3(y+4) f^(-1)(x) = (3(x+4)) f(f^(-1)(x)) = f(3(x+4)) = (1/3)(3(x+4)) -4 = (1/3)(3x+12)-4 = x+4-4 = x
or (1/3)x - 4 = x (1/3)x - x = 4 x((1/3)-1) = 4 x = 4/(-2/3) = -6
-6 is the answer thank you
yeah I read it wrong the first time.
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