. Essay. According to the U. S. Census Bureau, the total 2008 U.S. population was 303,824,640. The chart below summarizes the 2008 population for five U.S. States. U. S. State 2008 Population Alaska 686,293 California 36,756,666 Hawaii 1,288,198 Idaho 1,523,816 Indiana 6,376,792 SOURCE: U. S. Census Bureau What is the probability that a randomly selected U.S. resident did not live in Alaska? Show step by step work. Round solution to the nearest thousandth.
Probability is the chance of something being true. Just divide the number of U.S. residents who do not live in Alaska by the number of U.S. residents.
to find the # of people who do not live in alaska People in USA - People in Alaska
4. Essay. According to the U. S. Census Bureau, the total 2008 U.S. population was 303,824,640. The chart below summarizes the 2008 population for five U.S. States. U. S. State 2008 Population Alaska 686,293 California 36,756,666 Hawaii 1,288,198 Idaho 1,523,816 Indiana 6,376,792 SOURCE: U. S. Census Bureau having problems .
How many US residents don't live in Alaska?
would i add the 4 other states
Start with the total population of the US in 2008. It was 303,824,640.
so i take the population and subtract alaka fom that?
right
that will give you th # of people who do not live in Alaska
then divide # of people who do not live in alaska ------------------------------- # of people in USA
442.70397 rounded to the nearest thousad.443 would that be right
how did you get 442.70397?
i divided the top and bottom and got that what did i do wrong
how many people do not live in alaska? usa - alaska 303,824,640 - 686,293 = 303,138,347
do you see where these numbers came from?
yes
no divide people who do not live in alaska / people in USA 303,138,347 / 303,824,640 do you see where those numbers came from?
no divide them
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