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An acute angle θ is in a right triangle with sin θ =2/3 . What is the value of cot θ?
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|dw:1344983152523:dw| now by using pythagoras theorem find the third side
9+4=13
let's say third side is x then x=\[\sqrt{3^2-2^2}\]
x=\[\sqrt{5}\]
and then
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then cot theta= base/perpendicular= \[\sqrt{5}/2\]
lifesaver !!
i guess !! by the way according to pythagoras theorem 3^2= 2^2+sqrt5^2
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