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OpenStudy (anonymous):
Can someone help me plz?
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OpenStudy (anonymous):
What are the vertices of the hyperbola given by the equation x^2/16 - y^2/36 = 1?
hero (hero):
Still working on this, huh? Did you even read what was posted on the purplemath website?
OpenStudy (anonymous):
yes i did...but i didnt understand it
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