Fill in the missing term so that the quadratic equation has a graph that opens up, with a vertex of
(– 2, – 16), and x intercepts at x = -6 and x = 2. (Do not include the negative sign in your answer.)

y = x2 + 4x − ___

Question

Fill in the missing term so that the quadratic equation has a graph that opens up, with a vertex of 
(– 2, – 16), and x intercepts at x = -6 and x = 2. (Do not include the negative sign in your answer.) 

y = x2 + 4x − ___

anonymous · Answer

wow tmi

anonymous · Answer

in any case you know it looks like 
$$y=a(x+6)(x-2)$$ and since your answer has leading coefficient 1 it must be 
$$y=(x+6)(x-2)=x^2+4x-12$$

anonymous · Answer

if $(-2,-16)$ in on the graph, then good, if not, the problem is not solvable,