Question

Please help! Perform indicated operation and leave answer in a+bi form :/ (7+2i)/(4-3i)
a. 22/25-13/25i
b. 34/25-13/25i
c. 34/25+29/25i
d. 22/25+29/25i

Answer 1

\[\frac{7+2i}{4-3i} =\]\[=\frac{7+2i}{4-3i}\times1 \]\[=\frac{7+2i}{4-3i}\times\frac{4+3i}{4+3i} \]\[=\frac{(7+2i)(4+3i)}{4^2-3^2i^2}\]\[=\]

Answer 2

d. Thanks! :)