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another one..
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this question better blow my mind
\[\frac{ x ^{-1}-1-6x }{ x ^{-1} +2 } \rightarrow \frac{ \frac{ 1 }{ x }-1-6x }{\frac{ 1 }{ x }+2}\]
so do I give them all a common denominator?
yea, x.
okay
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so :\[\frac{ \frac{ 1-x-6x ^{2} }{ x } }{ \frac{ 1+2x }{ x } }\]
is that right?
yes. Absolutely. Go on.
okay ^^ then \[\frac{ 6x ^{2}-x-1}{ 1+2x }\]
-6x^2
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+1 also
okay thank you :)
so :\[\frac{ (-3x+1)(2x+1) }{ 1+2x } \rightarrow 1-3x\] ^^
Oh yeah. ^^
thank you for the help!
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you super smart @bronzegoddess
wow, thank you.. but I doubt it lol :)
you're very kind @bronzegoddes. I merely watched you do all the work. lol.
thx, your help was appreciated.. NEXT ONE :P
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