Question

radicals =.=

Answer 1

\[\frac{ 5 }{ \sqrt{2}+\sqrt{3}+\sqrt{8} } \times \frac{ \sqrt{2}-\sqrt{3}-\sqrt{8} }{ \sqrt{2}-\sqrt{3}-\sqrt{8} }\]

Answer 2

right?

Answer 3

@mathslover

Answer 4

@waterineyes

Answer 5

this will complicate it..

Answer 6

\[\sqrt{8 } = 2\sqrt{2}\]

Answer 7

yes..

Answer 8

yes, thats what i thought :) thx yahoo

Answer 9

\[\sqrt{2} + 2\sqrt{2} = 3\sqrt{2}\]

Answer 10

nw can u solve @bronzegoddess

Answer 11

just try to do some hard work

Answer 12

Multiply and divide by : \(3\sqrt{2} - \sqrt{3}\)

Answer 13

okay \[\frac{ 5 }{ 3\sqrt{2} +\sqrt{3}} \times \frac{ 3\sqrt{2}-\sqrt{3} }{ 3\sqrt{2}-\sqrt{3} } \rightarrow \frac{ 15\sqrt{2}-5\sqrt{3} }{6-9 }\]

Answer 14

Check the denominator part..

Answer 15

Yup

Answer 16

a^- b^2

Answer 17

okay lemme work using paper lol

Answer 18

\[(a+b)(a-b) = a^2 - b^2\]

Answer 19

9*2 -3

Answer 20

18-3 = 15

Answer 21

@Yahoo! let him try..

Answer 22

am a she lol

Answer 23

sorry!! @bronzegoddess

Answer 24

Then :

@Yahoo! let her try..

Ha ha ha..

Answer 25

@waterineyes u see "goddess"

Answer 26

okay I get it (\[(3\sqrt{2}-\sqrt{3})(3\sqrt{2}+\sqrt{3}) = 9 \times2-3= 15\]

Answer 27

I did not ..

But now I saw..

Ha ha ha..

My mistake..

Answer 28

Yes..

Answer 29

@waterineyes ==== Used to say welcome dear ....if u say thxx @bronzegoddess

Answer 30

You can do more in that..

Answer 31

so...type some thing else

Answer 32

lol y'all are like an old couple :P I ma working on the final answer :)

Answer 33

@Yahoo! ha haha..

Answer 34

ha...haa

Answer 35

But @Yahoo! we have not got final answer yet..

Answer 36

Yes..... @bronzegoddess u got

Answer 37

\[\frac{3\sqrt{2}-\sqrt{3} }{ 3 }\]

Answer 38

Yep..

Answer 39

thank you! ^^ for the help

Answer 40

Welcome dear..

@Yahoo! ha haha..

Answer 41

i wish I could give two medals

Answer 42

I can..

Answer 43

:o, to two different people?

Answer 44

Yes I did..
Don't worry..

Answer 45

okay thank you!^^

Answer 46

Welcome dear..