Question

Let a and b be the roots of x^2 - 6x - 2 =0 with a>b . if cn = a^n - b^n for n>=1 then the value of (c10-2c8)/2c9

Answer 1

@dumbcow @satellite73 @experimentX

Answer 2

??

Answer 3

if a b be the roots then
a*b= 2
and a+b=6

Answer 4

ab = -2

Answer 5

ooops typo

Answer 6

(c10-2c8)/2c9 ??

Answer 7

if cn = a^n - b^n

Answer 8

now try to love \[a ^{10}-b ^{10}= (a ^{5}-b ^{5}) (a ^{5}+b ^{5})\]
like this

Answer 9

hey..hw to get rid off ^5

Answer 10

you will see when you will take \[a ^{4}+b ^{4}\]
common out of numerator
just solve it like i said and you will see

Answer 11

try playing with this.