Question

sinx - sin3x / sin^2 - cos^2x = 2sinx . prove.

Answer 1

- ( sin 3x - sinx)

Answer 2

sinx - sin3x = - ( sin 3x - sinx)

Answer 3

okay

Answer 4

den??

Answer 5

sin^2 - cos^2x = -(cos ^ 2 x - sin^2 x)

Answer 6

ok

Answer 7

cos ^ 2 x - sin^2 x = Cos 2A

Answer 8

what's A??

Answer 9

sorry cos ^ 2 x - sin^2 x = Cos 2x

Answer 10

okay

Answer 11

so...just solve them

Answer 12

( sin 3x - sinx) =

Answer 13

2 cos 2x sinx / cos 2x = 2 sin x

Answer 14

u got it.....)))

Answer 15

thanks a lot !!

Answer 16

yw.......