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prove that sec 8A-1 / sec 4A-1 = tan 8A/tan 2A.
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tan^x + 1 = sec^2 x
tan^2 x + 1 = sec^2 x
what is this ?
it is a formula
sec 8A = sec 2(4A)
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how do i use it ?
aha.... got it..
Sec 8A = 1/cos 8A
okay ..
nw Cos 8A = Cos 2 (4A)
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