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OpenStudy (anonymous):
prove that sec 8A-1 / sec 4A-1 = tan 8A/tan 2A.
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OpenStudy (anonymous):
tan^x + 1 = sec^2 x
OpenStudy (anonymous):
tan^2 x + 1 = sec^2 x
OpenStudy (anonymous):
what is this ?
OpenStudy (anonymous):
it is a formula
OpenStudy (anonymous):
sec 8A = sec 2(4A)
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OpenStudy (anonymous):
how do i use it ?
OpenStudy (anonymous):
aha.... got it..
OpenStudy (anonymous):
Sec 8A = 1/cos 8A
OpenStudy (anonymous):
okay ..
OpenStudy (anonymous):
nw Cos 8A = Cos 2 (4A)
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OpenStudy (anonymous):
|dw:1345047758107:dw|
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