Question

Binomial Theorem: (a+b)^n=?

Answer 1

\[(a+b)^n=\sum_{k=0}^n\binom nka^{n-k}b^k\text{ where }\binom nk={n!\over k!(n-k)!}\]

Answer 2

Wow.. your good. I'm pretty sure that is exactly what I was looking for.

Answer 3

welcome
I don't like giving out straight answers, but I don't know how to derive that, so you got lucky :)

Answer 4

Thanks I appreciate that :)