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find the values of k so that the given condition is satisfied the graph of y=1/2 x^2 -kx +2 is tangent to the x-axis
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Tangent to the x-axis Well the x-axis is horizontal and so y=0 has slope what?
does a line have a tangent?
pfft, i read it wrong :)
Find y' and evaluate it at x=a and set that equal to the slope of y=0 I will draw a visual sorta related to this question |dw:1345053131573:dw| Pretend that curly thing is your function
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