Question

help me find int_{0}^{1} x sqrt{x^2+1}dx =

Answer 1

u-sub\[u=x^2+1\]

Answer 2

\[\int\limits_{0}^{1} x \sqrt{x^2+1}dx = \]

Answer 3

i think u=sprt(x^2+1) better

Answer 4

(a)\[2\sqrt{2}-1/3\]
(b)\[2(2\sqrt{2}-1)/3\]

Answer 5

if\[u=x^2+1\]then\[du=?\]