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Find the range of the function. f(x) = (x – 2)^2 + 2 (2 points) All real numbers y ≥ 0 y > 2 y ≥ 2
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hint \[(x-2)^2 \ge 0\]
can you show me how you got that
u dont need to get that from somewhere square of every real number is greater than or equal to zero
can u tel me what is the final answer plz?
y ≥ 0
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\[(x-2)^2\ge 0\]add 2 to both sides\[(x-2)^2+2\ge 2\]
y ≥ 2?
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