Question

What is the equation of the line?

Answer 1

y=x-1
y=-x-3
y=-3x+1
y=-3x
y=-x+3
y=x+3

Answer 2

answer choices ^

Answer 3

We have two coordinates (0,3) and (3,0). first let us find the gradient m.
\(\large m=\LARGE\frac{y_2-y_1}{x_2-x_1}\)
\(\large m=\LARGE\frac{0-3}{3-0}\)
\(\large m=\LARGE\frac{-3}{3}\)
\(\large m=-1\)
Nw let us take one of the points (0,3) and find the eqn.
\(\large m=\LARGE\frac{y-y_1}{x-x_1}\)
\(\large -1=\LARGE\frac{y-3}{x-0}\)
\(\large -1=\LARGE\frac{y-3}{x}\)
\(\large -x=y-3\)
\(\large -x+3=y\)
\(\large y=-x+3\)
Is that clear?