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OpenStudy (anonymous):
Verify the identity. 1/sin^2x+1/cos^2x = 1/sin^2x-sin^4x
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OpenStudy (ghazi):
is your question correct?
OpenStudy (ghazi):
is it sin2x or sin^2x
OpenStudy (anonymous):
sin^2x. my question is correct
hartnn (hartnn):
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