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verify. cosxtan^3x=sinxtan^2x
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u have to use\[\tan x=\frac{\sin x}{\cos x}\]
yeahh but im kind of confused on how to for this questions
\(\cos x\tan^3x=\cos x \tan x \ \tan^2x\) ------
how did you get cosxtanx for the right side?
well exponent of \(\tan x\) is 3 i can write it like this\[\tan^3 x=\tan x \tan^2 x\]
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like \(a^3=a.a^2\)
oh okayy
um and then what is the next step ?
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