Mathematics
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OpenStudy (anonymous):
if the 7th term is in a geomteric sequence is 64 and the common ration is -2 what are the 1st term and the 14th term
helpppp
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OpenStudy (anonymous):
general term of a g s is a.r^(n-1)
so
a(-2)6 = 64 so a =?
OpenStudy (anonymous):
-12?
OpenStudy (anonymous):
sry wat i meant was (-2)^6
OpenStudy (anonymous):
so this would be the steps (-2)^6=64 and what would a =?
OpenStudy (anonymous):
thats the part that i dont get
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OpenStudy (anonymous):
wat do u think?
OpenStudy (anonymous):
multiply -2 * 6 get the answere and then subtract it by 64?
OpenStudy (anonymous):
this a geometric prog.......so u dont subtract.........u just multiply nd divide stuff
OpenStudy (anonymous):
-5.333??? it cant be a decimal
OpenStudy (anonymous):
-.- ax64 = 64 so a=?
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OpenStudy (anonymous):
768?
OpenStudy (anonymous):
how did u get that?
a = 64/64 so a=?
OpenStudy (anonymous):
i multiplied 12 and 64
OpenStudy (anonymous):
the answere 1?
OpenStudy (anonymous):
yea
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OpenStudy (anonymous):
so for the 14 th term
1*(-2)^(14-1) = ?
OpenStudy (anonymous):
can u show the steps? please
OpenStudy (anonymous):
jus use that formula nth term in a gp is a*r*r*r*r....... (n-1) times
OpenStudy (anonymous):
-8192?
OpenStudy (anonymous):
is it that?
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OpenStudy (anonymous):
how did u get -8192?
OpenStudy (anonymous):
it's (-2)^13
OpenStudy (anonymous):
yea u r right
OpenStudy (anonymous):
thank u so much ! and thank u for your time!