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Solve for X: 8^(3x)=16^(x-5)
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x = -4
i need to know how u got that not just the answer.
rewrite 8 and 16 as powers of 2
8^(3x)=2^(9x) 16^(x-5)=2^(4(x-5)) Now solve 9x=4x-20 -> 5x=-20 -> x=-4
(2)^3*3x=2^4*(x-5)...equate the powers ....9x= 8(x-5)
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since 2^3=8 and 2^4=16
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