Question

@rayford

here is your question


simplify \[\cfrac {2x^2-50}{x-5}\]

Answer 1

take out 2 common from the numerator

\[\cfrac {(2)(x^2-25)}{x-5}\]

you know that \[\color{red}{a^2 - b^2 = (a+b)(a-b)}\]

now using this identity

\[\large x^2 - 25 = \color {red} {(x+5)} \color {green}{(x-5)}\]

Now you solve the fraction further

@rayford