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Solve 7^x – 5 = 7^4x + 7
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is it : \[\large{7^{x-5}=7^{4x+7}}\]
Yes it is
ok so since bases are same powers will be equal that is x-5 = 4x+7
can u solve for x now?
so x=4x+13 now i divide 4 correct?
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mistake there... check it up 7+5 is not equal to 13
im sorry I meant x=4x+12 so now I divide by 4 correct?
no don't divide by 4 subtract 4x both sides
okay so I got -4x= 12 now what should i do?
I believe I divide -4?
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I think you did mistake again : \[\large{x=4x+12}\] \[\large{\color{violet}{x-4x=4x-4x+12}}\] \[\large{\color{red}{-3x=12}}\]
nod divide by -3
so would my answer be x=-4?
yes right
Thank you so much!
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welcome dear also: \[\huge{\cal{Welcome}\space \mathsf{To}\space \cal{ openstudy}}\]
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