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8(4x-2)=4(8x+6)
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divide 4 both sides what do you get?
\[\large{\frac{8(4x-2)}{4}=\frac{4(8x+6)}{4}}\]
It cannot be solved? Left side: 8(4x) = 32x Right side: 4(8x) = 32x They cancel out
there's no solution to this problem
Yeah :)
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.. right
does that mean that the solution set is empty
yes right
\[\large{\textbf{Solution set}=\phi }\]
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