Ask your own question, for FREE!
Mathematics 15 Online
OpenStudy (anonymous):

prove x^2 +x is odd, even, or neither.

OpenStudy (lgbasallote):

you can prove by graphing...

OpenStudy (anonymous):

one exponent is even one is odd neither

OpenStudy (anonymous):

for a polynomial to be even, all exponents must be even for odd, odd

OpenStudy (vishweshshrimali5):

if u mean odd function then put -x in place of x

OpenStudy (anonymous):

which explains the terminology

OpenStudy (lgbasallote):

though it doesnt work in trig functions....

OpenStudy (vishweshshrimali5):

u will get x^2 - x which is neither -f(x) or f(x) so it is neither odd nor even

OpenStudy (anonymous):

sure it does

OpenStudy (vishweshshrimali5):

@koopineapple did u mean odd function, even function etc.

OpenStudy (anonymous):

yes

OpenStudy (vishweshshrimali5):

then for odd function f(-x) = -f(x) and for even function f(-x) = f(x) try putting -x in place of x

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!