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7 + 2y = 8x 3x - 2y = 0 Solve the system of equations by substitution.
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find the value of y in terms of x from second eq. and put it in first
3x - 2y = 0 \[\large x = \cfrac{2y}{3}\] put this value of x in first eq. to get value of y
First I would put one equation in in y=mx+b format y=4x-7/2 Use that and plug it into your other equation. 3x-2(4x-7/2)=0 From there work it out to find your x Once you've found your X, plug your x into original problem to solve for Y
thanks a lot :)
No problem (:
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