Question

Solve for x in the proportion

Answer 1

http://learn.flvs.net/webdav/assessment_images/educator_algebra1_v10/10_02_17a.gif

Answer 2

just cross multiply

Answer 3

2x^2= -16x-30

Answer 4

add 16x and 30 to both sides
2x^2+16x+30=0

Answer 5

and so on.

Answer 6

cross multiplying
\[2x ^{2} = -[16x + 30]\]
\[2x ^{2} = -16x - 30\]
\[2x ^{2} + 16x + 30 = 0\]
dividing throughout by 2
\[x ^{2} + 8x + 15 = 0\]
splitting the middle term
\[x ^{2} + (5x + 3x) + 15 = 0\]
on grouping and taking common out
\[x ( x + 5) + 3 (x + 5) = 0\]
\[(x + 3)(x + 5) = 0\]
we can write

x + 3 = 0 and x + 5 = 0

therefore, x = (-3) and x = (-5)