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Mathematics 21 Online
OpenStudy (anonymous):

Solve?

OpenStudy (anonymous):

\[\sin ^2 5 + \sin ^2 10 ................+ \sin^290/ ( 1 + \cos ^2 5 .......+ \cos^2 90)\]

OpenStudy (anonymous):

90 = 5 + 5n - 5 n = 18 ==== sin terms Value = 9

OpenStudy (anonymous):

90 = 5 + 5n - 5 n = 18 ==== cos terms value = 10

OpenStudy (anonymous):

i got answer as 9/10

OpenStudy (anonymous):

but it is wrong.....

OpenStudy (anonymous):

The answer should be 1

OpenStudy (anonymous):

@shubhamsrg @shubhamsrg @shubhamsrg @shubhamsrg @shubhamsrg @shubhamsrg

OpenStudy (anonymous):

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mathslover (mathslover):

yahoo what is this

OpenStudy (shubhamsrg):

obviously its 1 .. sin^2 5 = cos^2 85 thus sin^2 85 + sin^2 5 =1 same with denom.. num = denom ans = 1

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