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if f(x)=1-x^2, what is the range of f?
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First wat is the Domain can u find out
i dont know the domain
y = 1 - x^2 x^2 = 1-y x = sqrt 1-y
so it should not be a complex number
the final answer is f(x) is greater than or equal to 1
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1 - y > =0 y < = 1
Range = [1 , infinity)
Did u understand
no how do you get that answer?
take y = f(x)
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okay then what?
f(x)=1-x^2
y = 1 - x^2 x^2 = 1-y x = sqrt 1-y
i get it
ok.....
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u have more question on this topic??
just inform me
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